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My Trial :: $\displaystyle \int_{0}^{1991}\left\{\frac{(2x+2)+3}{x+1}\right\}\cdot [x]dx$

$\displaystyle \int_{0}^{1991}\left\{2+\frac{3}{x+1}\right\}[x]dx = \int_{0}^{1991}\left\{\frac{3}{x+1}\right\}[x]dx$

Using the formula $\left\{z+x\right\} = \left\{x\right\}$,where $z$ is an Integer

Now How can i slve after that

Help me

Thanks